2(x-8)^2-x(4-x)=3x^2+2

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Solution for 2(x-8)^2-x(4-x)=3x^2+2 equation: 



2(x-8)^2-x(4-x)=3x^2+2

We move all terms to the left:

2(x-8)^2-x(4-x)-(3x^2+2)=0

We add all the numbers together, and all the variables

2(x-8)^2-x(-1x+4)-(3x^2+2)=0

We multiply parentheses

1x^2+2(x-8)^2-4x-(3x^2+2)=0

We get rid of parentheses

1x^2-3x^2+2(x-8)^2-4x-2=0

We add all the numbers together, and all the variables

-2x^2-4x+2(x-8)^2-2=0

We move all terms containing x to the left, all other terms to the right

-2x^2-4x+2(x-8)^2=2

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